Find the area of a triangle Geometry

27

12

7.5

15

\dfrac{9{\sqrt{3}} }{2}

\dfrac{3{\sqrt{3}} }{2}

3{\sqrt{3}}

9

12

18

24

36

\dfrac{{\sqrt{3}} }{2}

2\sqrt{3}

4{\sqrt{3}}

8

\dfrac{3}{2}\left(4+\sqrt{27}\right)

\dfrac{2}{3}\left(4+\sqrt{27}\right)

4+\sqrt{27}

3\left(4+\sqrt{27}\right)

1

{{\sqrt{2}} }

2{\sqrt{2}}

\dfrac{1}{2}

\sqrt{2}

2\sqrt{2}

2

4