Make conjecture about limits from graphs Calculus

\lim\limits_{x \to\infty }f\left(x\right) doesn't exist.

\lim\limits_{x \to\infty }f\left(x\right)=+\infty

\lim\limits_{x \to\infty }f\left(x\right)=4

\lim\limits_{x \to\infty }f\left(x\right)=2

\lim\limits_{ x \to \infty} f\left(x\right) \text{ does not exist.}

\lim\limits_{ x \to \infty} f\left(x\right) = 0^+

\lim\limits_{ x \to \infty}f\left(x\right) \text{ is either a positive or negative number.}

\lim\limits_{ x \to \infty} f\left(x\right) = 0

\lim\limits_{ x \to \infty} f\left(x\right) \text{ does not exist.}

\lim\limits_{ x \to \infty} f\left(x\right) = 0.

\lim\limits_{ x \to \infty}f\left(x\right) \text{ is a positive number.}

\lim\limits_{ x \to \infty} f\left(x\right) = +\infty

\lim\limits_{x \to \infty} f\left(x\right) = 4

\lim\limits_{x \to \infty} f\left(x\right) = 2\\

\lim\limits_{x \to \infty} f\left(x\right) = 10

\lim\limits_{x \to \infty} f\left(x\right) \text{ does not exist.}

\lim\limits_{x \to \infty} f\left(x\right) = 0.

\lim\limits_{x \to \infty} f\left(x\right) = +\infty\\

\lim\limits_{x \to \infty} f\left(x\right) = -\infty\\

\lim\limits_{x \to \infty} f\left(x\right) \text{ does not exist.}

\lim\limits_{x \to \infty} f\left(x\right) = +\infty

\lim\limits_{x \to \infty} f\left(x\right) \text{ cannot be determined.}\\

\lim\limits_{x \to \infty} f\left(x\right) = 15

\lim\limits_{x \to \infty} f\left(x\right) \text{ does not exist.}

\lim\limits_{x \to 5} f\left(x\right) = \text{ does not exist.}

\lim\limits_{x \to 5} f\left(x\right) = 0.

\lim\limits_{x \to 5} f\left(x\right) = 5.

\lim\limits_{x \to \infty} f\left(x\right) = -\infty.

\lim\limits_{x \to \infty} f\left(x\right) \text{ does not exist.}

\lim\limits_{x \to \infty} f\left(x\right) = 0.

\lim\limits_{x \to \infty} f\left(x\right) = 5.

\lim\limits_{x \to \infty} f\left(x\right) = -\infty.