Find the limit of a polynomial Calculus

Find the following limits.

\lim\limits_{x \to \infty} \left(3x^3-2x^2+4\right)

f has no limit as x approaches infinity.

\lim\limits_{x \to \infty} f\left(x\right)=3

\lim\limits_{x \to \infty} f\left(x\right)=\infty

\lim\limits_{x \to \infty} f\left(x\right)=-\infty

\lim\limits_{x \to \infty} \left(-x^2 + 2x -1\right)

\lim\limits_{x \to \infty} f\left(x\right)=-\infty

\lim\limits_{x \to \infty} f\left(x\right)=\infty

\lim\limits_{x \to \infty} f\left(x\right)=-1

f has no limit as x approaches infinity.

\lim\limits_{x \to 4} \left(2x^2 - 4x + 5\right)

\lim\limits_{x \to 4} f\left(x\right)= 21

\lim\limits_{x \to 4} f\left(x\right)=5

\lim\limits_{x \to 4} f\left(x\right)=-3

\lim\limits_{x \to 4} f\left(x\right)=37

\lim\limits_{x \to \infty} \left(2x^2 - 4x + 5\right)

\lim\limits_{x \to \infty} f\left(x\right)=\infty

\lim\limits_{x \to \infty} f\left(x\right)=-\infty

\lim\limits_{x \to \infty} f\left(x\right)=-1

f has no limit as x approaches infinity.

\lim\limits_{x \to -\infty} \left(-5x^7 + x^4 + 3x^2 - x\right)

\lim\limits_{x \to -\infty} f\left(x\right)=\infty

\lim\limits_{x \to -\infty} f\left(x\right)=-\infty

\lim\limits_{x \to -\infty} f\left(x\right)=-1

f has no limit as x approaches negative infinity.

\lim\limits_{x \to \infty} \left(-x^3 + 4x^2 - 2x + 3\right)

\lim\limits_{x \to \infty} f\left(x\right)=-\infty

\lim\limits_{x \to \infty} f\left(x\right)=\infty

\lim\limits_{x \to \infty} f\left(x\right)=-1

f has no limit as x approaches infinity.

\lim\limits_{x \to -\infty} \left(4x^4 + 2x^2 + 6\right)

\lim\limits_{x \to -\infty} f\left(x\right)=\infty

\lim\limits_{x \to -\infty} f\left(x\right)=-\infty

\lim\limits_{x \to -\infty} f\left(x\right)=-1

f has no limit as x approaches negative infinity.