Find the value of x in the following triangles. x = \sqrt{34} x=4 x=8 x= \sqrt{15} x=10 x=14 x=12 x= \sqrt{14} x=4 x=\sqrt{34} x=16 x= \sqrt{8} x = \sqrt{39} x=4 x=7 x= \sqrt{89} x = \sqrt{75} x=5 x=7 x= \sqrt{15} \sqrt{50} x=5 x=10 x= \sqrt{15} x = \sqrt{28} x=5 x=\sqrt{8} x= \sqrt{7}