Solve the following equations.
\lfloor x-\dfrac{2}{3} \rfloor=4
\lfloor 2x+\dfrac{5}{6} \rfloor=3
\lfloor 4x-\dfrac{1}{2} \rfloor=7
\lfloor 3x-5 \rfloor=1
\lfloor \dfrac{1}{3}x+\dfrac{5}{6} \rfloor=2
\lfloor \dfrac{2}{5}x-\dfrac{7}{6} \rfloor=5
\lfloor 3x+\dfrac{1}{7} \rfloor=0