Calculate basic probabilities - High school Statistics & Probabilities Exercises

Paul throws an unbiased die.

Let A be the event : "the result is even".

Let B be the event : "the result of the die is greater than or equal to 3".

Find P\left(A\cap B\right).

P\left(A\cap B\right)=0.44

P\left(A\cap B\right)=\dfrac46

P\left(A\cap B\right)=\dfrac13

P\left(A\cap B\right)=0

In a bag there are 5 red marbles, 10 blue marbles, 15 green marbles, and 20 yellow marbles. Joey picks a marble.

What is the probability of Joey picking a blue marble?

Let E be the event "Joey pick a blue marble".

\dfrac{1}{5}

\dfrac{1}{10}

\dfrac{3}{10}

\dfrac{2}{5}

In a bag there are 10 red cards numbered 1 through 10 and 7 blue cards numbered 1 through 7.

Bob is picking a card.

Let A be the event: "the color of the card is red."

Let B be the event: "the number on the card is greater than 6."

Find P\left(A\cap B\right).

P\left(A\cap B\right)=\dfrac{4}{17}

P\left(A\cap B\right)=\dfrac{7}{17}

P\left(A\cap B\right)=\dfrac{10}{17}

P\left(A\cap B\right)=\dfrac{12}{17}

At a local car dealership there are 20 new trucks and 19 new cars. Also, at the same dealership there are 5 second-hand trucks and 16 second-hand cars.

Determine the probability that a randomly selected vehicle is new.

Let E be the event "The selected vehicle is new".

\dfrac{13}{20}

\dfrac{19}{60}

\dfrac{1}{3}

\dfrac{1}{4}

Mark throws an unbiased die.

Let A be the event : "the result is odd".

Let B be the event : "the result of the die is greater than or equal to 4".

Find P\left(A\cup B\right).

P\left(A\cup B\right)=\dfrac{5}{6}

P\left(A\cup B\right)=\dfrac{2}{3}

P\left(A\cup B\right)=\dfrac{1}{2}

P\left(A\cup B\right)=\dfrac{1}{3}

In a bag there are 12 green cards numbered 1 through 12 and 10 yellow cards numbered 1 through 10.

Luke is picking a card.

Let A be the event: "the color of the card is yellow."

Let B be the event: "the number on the card is greater than 8."

Find P\left(A\cap B\right).

P\left(A\cap B\right)=\dfrac{1}{11}

P\left(A\cap B\right)=\dfrac{5}{11}

P\left(A\cap B\right)=\dfrac{6}{11}

P\left(A\cap B\right)=\dfrac{2}{11}