Find the equation of a linear function from a graph Precalculus

Determine an expression of the linear functions f whose graphs are the following ones. If no function exists, determine the equation of the straight line.

f\left(x\right)=2x-0.5

f\left(x\right)=-0.5x+2

f\left(x\right)=-0.5x-2

f\left(x\right) = 0.5x-2

f\left(x\right) = x + 1

f\left(x\right) = -x + 1

f\left(x\right) = -x - 1

f\left(x\right) = x - 1

f\left(x\right) = x - 1

f\left(x\right) =- x + 1

f\left(x\right) = x + 1

f\left(x\right) =- x - 1

x=-2

x=2

f\left(x\right)=-2

f\left(x\right)=2

x=-1

y=1

x=1

y=-1

f\left(x\right) = -2x - 2

f\left(x\right) = -2x + 2

f\left(x\right) = 2x + 2

f\left(x\right) = -2x - 2

f\left(x\right) = 2x - 1

f\left(x\right) = 2x + 1

f\left(x\right) = -2x - 1

f\left(x\right) = -2x + 1