Calculate expressions involving absolute values Precalculus

Let f be the function defined as f\left(x\right)=\left| 2x- 4\right|.

What is f\left(3\right) ?

f\left(3\right)=-1

f\left(3\right)=1

f\left(3\right)=2

f\left(3\right)=3

Let f be the function defined as f\left(x\right)=\left| x^2+4x+3\right|.

What is f\left(-1\right) ?

f\left(-1\right)=0

f\left(-1\right)=-2

f\left(-1\right)=6

f\left(-1\right)=8

Let f be the function defined as f\left(x\right)=\left| x^2- 2\right|.

What is f\left(\dfrac{1}{2}\right) ?

f\left(\dfrac{1}{2}\right) = \dfrac{4}{7}

f\left(\dfrac{1}{2}\right) = \dfrac{7}{4}

f\left(\dfrac{1}{2}\right) = \dfrac{3}{2}

f\left(\dfrac{1}{2}\right) = \dfrac{3}{4}

Let f be the function defined as f\left(x\right)=\left| x^3- 8\right|.

What is f\left(-2\right) ?

f\left(-2\right)=0

f\left(-2\right)=16

f\left(-2\right)=14

f\left(-2\right)=2

Let f be the function defined as f\left(x\right)=\dfrac{\left| x+1\right|}{|x^2-2|}.

What is f\left(1\right) ?

f\left(1\right)=0

f\left(1\right)=\dfrac{2}{3}

f\left(1\right)=\dfrac{1}{2}

f\left(1\right)=2

Let f be the function defined as f\left(x\right)=\dfrac{|x^2-x-1|}{|\left(x-1/2\right)^3|}.

What is f\left(0\right) ?

f\left(0\right)=6

f\left(0\right)=\dfrac{1}{6}

f\left(0\right)=8

f\left(0\right)=\dfrac{1}{8}

Let f be the function defined as f\left(x\right)=\dfrac{x-1}{|x-1|}.

What is f\left(-\dfrac{1}{2}\right) ?

f\left(-\dfrac{1}{2}\right)=-1

f\left(-\dfrac{1}{2}\right)=1

f\left(-\dfrac{1}{2}\right)=-\dfrac{1}{2}

f\left(-\dfrac{1}{2}\right)= \dfrac{1}{2}