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  1. Home
  2. 12th grade
  3. Algebra I
  4. Exercise : Multiply real numbers

Multiply real numbers Algebra I

Evaluate 3 \times a \times b with a=2.4 and b=\dfrac{3}{12}

We have:

b=\dfrac{3}{12} = 0.25

Substituting in the values for a and b into the expression, we have:

3 \times a \times b = \left(3\right)\left(2.4\right)\left(0.25\right)

Then we have:

\left(3\right)\left(2.4\right)\left(0.25\right) = \left(7.2\right)\left(0.25\right)=1.8

3\times a\times b=1.8

Evaluate a \times 4 \times b with a=\dfrac{2}{5} and b=0.7

We have:

a=\dfrac{2}{5} = 0.4

Substituting in the values for a and b into the expression, we have:

a \times 4 \times b = \left(0.4\right)\left(4\right)\left(0.7\right)

Then we have:

\left(0.4\right)\left(4\right)\left(0.7\right) = \left(1.6\right)\left(0.7\right)=1.12

a\times 4\times b=1.12

Evaluate 7 \times c \times d with c=\dfrac{1}{10} and d=-1.5

We have:

c=\dfrac{1}{10} = 0.1

Substituting in the values for c and d into the expression, we have:

7 \times c \times d = \left(7\right)\left(0.1\right)\left(-1.5\right)

Then we have:

\left(7\right)\left(0.1\right)\left(-1.5\right) = \left(0.7\right)\left(-1.5\right)=-1.05

7\times c\times d=-1.05

Evaluate -2 \times c \times d with c=0.3 and d=\dfrac{-7}{14}

We have:

d=\dfrac{-7}{14} = 0.5

Substituting in the values for c and d into the expression, we have:

-2 \times c \times d = \left(-2\right)\left(0.3\right)\left(-0.5\right)

Then we have:

\left(-2\right)\left(0.3\right)\left(-0.5\right) = \left(-0.6\right)\left(-0.5\right)=0.3

-2\times c\times d=0.3

Evaluate -g \times 3 \times h with g=0.25 and h=\dfrac{-1}{4}

We have:

h=\dfrac{-1}{4} = -0.25

Substituting in the values for g and h into the expression, we have:

-g \times 3 \times h = \left(-0.25\right)\left(3\right)\left(-0.25\right)

Then we have:

\left(-0.25\right)\left(3\right)\left(-0.25\right) = \left(-0.75\right)\left(-0.25\right)=0.1\ 875

-g\times 3\times h=0.1\ 875

Evaluate -g \times h \times 4 with g=0.36 and h=\dfrac{1}{8}

We have:

h=\dfrac{1}{8} = 0.125

Substituting in the values for g and h into the expression, we have:

-g \times h \times 4 = \left(-0.36\right)\left(0.125\right)\left(4\right)

Then we have:

\left(-0.36\right)\left(0.125\right)\left(4\right) = \left(-0.045\right)\left(4\right)=-0.18

-g\times h\times 4=-0.18

Evaluate a \times \left(-b\right) \times c with a = -0.2 and b=-1.25 and c = -\dfrac{3}{8}

We have:

c=-\dfrac{3}{8} = -0.375

Substituting in the values for a and b and c into the expression, we have:

a \times \left(-b\right) \times c = \left(-0.2\right)\left(1.25\right)\left(-0.375\right)

Then we have:

\left(-0.2\right)\left(1.25\right)\left(-0.375\right) = \left(-0.25\right)\left(-0.375\right)=0.9\ 375

a \times \left(-b\right) \times c = 0.9\ 375

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See also
  • Course : Fundamentals of numbers
  • Exercise : Convert a sentence into a mathematical expression or an equation
  • Exercise : Classify real numbers
  • Exercise : Convert from decimals to fraction
  • Exercise : Evaluate an expression that involves any operation
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